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Statics - Planar force system

Reduction Of A Planar Arbitrary System Of Forces

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  3. Engineering mechanics
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  5. Statics - Planar force system
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  7. Reduction Of A Planar Arbitrary System Of Forces

Example 1

Example 1

The force system is given to be planar. a) Reduce the system at point A b) Reduce the system at point B c) Simplify the system to its simplest form. Draw the result of the reduction

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Example 2

Example 2

There is a flat force system. a) Reduce the system at point A b) Reduce the system at point B c) Reduce the system to its simplest form. Draw the result of the reduction \begin{aligned} &F_{1}=5 k N \\ &q_{2}=6 k N / m \\ &F_{3}=8 k N \end{aligned}

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Example 3

Example 3

A flat force system is given. a) Reduce the system at point A b) Reduce the system at point B c) Simplify the system to its simplest form. Draw the result of the reduction \begin{aligned} &F_{1}=6 \sqrt{41} k N \\ &F_{2}=12 k N \\ &F_{3}=5 \sqrt{5} k N \\ &F_{4}=3 \sqrt{2} k N \\ &F_{5}=2 \sqrt{13} k N \\ &F_{6}=\sqrt{29} k N \end{aligned}

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Example 4

Example 4

A flat force system is given. a) Reduce the system at point A b) Reduce the system at point B c) Simplify the system to its simplest form. Draw the result of the reduction \begin{aligned} &F_{1}=2 \sqrt{2} k N \\ &F_{2}=3 \sqrt{2} k N \\ &F_{3}=4 \sqrt{13} k N \\ &M_{4}=200 k N m \\ &M_{5}=k N m \\ &F_{6}=17 \sqrt{34} k N \\ &F_{7}=10 \sqrt{29} \mathrm{kN} \end{aligned}

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Example 5

Example 5

The force system is planar. a) Reduce the system at point A b) Reduce the system at point B c) Simplify the system to its simplest form. Draw the result of reduction. \begin{aligned} &q_{1}=2 \mathrm{kN} / \mathrm{m} \\ &q_{2}=6 \mathrm{kN} / \mathrm{m} \\ &q_{3}=6 \mathrm{kN} / \mathrm{m} \\ &q_{4}=5 \mathrm{kN} / \mathrm{m} \\ &q_{5}=10 \mathrm{kN} / \mathrm{m} \\ &q_{6}=1 \mathrm{kN} / \mathrm{m} \end{aligned}

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